if sin theeta=√3-1 then find the value of sec(90-theeta)
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Answered by
8
sec (90-theeta) =cosec theeta
cosec theeta =1/sin theeta
sin theeta =√3-1
then, cosec theeta =1/√3-1
cosec theeta =1/sin theeta
sin theeta =√3-1
then, cosec theeta =1/√3-1
Answered by
9
Hello friends...
Given that
sin theeta=√3-1
We have to find
sec(90-theeta) = ?.
Now
We know that
Sec( 90- x ) = cosec x
Here
sec(90-theeta) = cosec theta
= 1/ sin theta = 1/(√3-1)
= (√3+1)/ (√3-1)(√3+1) (rationalizing)
=( √3+1)/( 3-1) = (√3+1) /2 answer
•♦ hope it helps ♦•
Given that
sin theeta=√3-1
We have to find
sec(90-theeta) = ?.
Now
We know that
Sec( 90- x ) = cosec x
Here
sec(90-theeta) = cosec theta
= 1/ sin theta = 1/(√3-1)
= (√3+1)/ (√3-1)(√3+1) (rationalizing)
=( √3+1)/( 3-1) = (√3+1) /2 answer
•♦ hope it helps ♦•
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