Math, asked by sachumon, 1 year ago

if sin theeta=√3-1 then find the value of sec(90-theeta)

Answers

Answered by VijaykumarMDR
8
sec (90-theeta) =cosec theeta
cosec theeta =1/sin theeta
sin theeta =√3-1
then, cosec theeta =1/√3-1

Answered by Ankit1408
9
Hello friends...

Given that
sin theeta=√3-1
We have to find
sec(90-theeta) = ?.

Now
We know that
Sec( 90- x ) = cosec x

Here

sec(90-theeta) = cosec theta

= 1/ sin theta = 1/(√3-1)

= (√3+1)/ (√3-1)(√3+1) (rationalizing)
=( √3+1)/( 3-1) = (√3+1) /2 answer

•♦ hope it helps ♦•
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