Question

if sin thet = 3/4 , calculate cos thet and tan thet​

Answer 1

Answer:

we know that sin thet = 3/4

➡perpendicular = 3

➡hypotenuse = 4

which implies, base=√4^2-3^2

therefore cos thet = base/hypotenuse = √7/4

tan thet = perpendicular/base = 3/√7 = 3√7/7