Question

If sin theta = 1/3,find 2cot^2theta+2

Answer 1

Hey


The question is :-


Sin∅ = 1 / 3


So ,

Cosec∅ = 1 / sin∅


Cosec∅ = 3 .


Now ,


2Cot²∅ + 2


= 2 ( Cot² ∅ + 1 )


= 2 * Cosec²∅


[ By identity ]


= 2 * ( 3 ) ²


= 2 * 9

= 18


thanks :)

Answer 2

sin theta=1/3

cos theta=3/1

cot theta=sin/cos=3/1/3=9/1

2cot2 theta +2
2(9)^2+2
2×81+2
162+2=164