Question

If sin theta = 1/3 . Show that 3 cos theta minus 4 cos cube theta =0

Answer 1

Answer:

Let theta be ₹.

sin ₹ = 1/2

sin ₹ = sin 30°

₹ = 30°

to prove:-

3cos₹ - 4cos^3₹ = 0

3cos30° - 4cos^3 30° = 0

3( \sqrt{3} /2) - 4( \sqrt{3} /2)^{3} = 03(

3

/2)−4(

3

/2)

3

=0

0 = 0

Hence Proved

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