Question

if sin theta = 1/3 then find sin^2 theta - tan ^2 theta and sin^2 theta + tan^2 theta where q is in its 1st quadrant
do it fast plz it is very urgent ​

Answer 1

Step-by-step explanation:

Given, sinθ=5−4,π<θ<23π

cosθ=−1−(5−4)2=5−3,tanθ=34

(i)sin2θ=2sinθcosθ=2×(3−4)(5−3)=2524

(ii)cos2θ=2cos2θ−1=2(5−3)2−1=2518−1=25−7

(iii)tan2θ=cos2θsin2θ=−7/2524/25=7−24