Question

if sin theta=1/3 then find the value of 2cot2 theta+2

Answer 1

Sin theta =perpendicular /hypotenuse   So  if  sin theta =1/3 then perpendicular =1x , hypotenuse =3x Let base be b b^2 + (1x)^2 =(3x)^2 b^2=9x^2-1x^2 b^2=8x^2 b=2√2x Cot theta  = B/P=(2√2x)/1x =  2√2 So 2 cot theta=2*2√2=4√2 And 2cot theta +2= 4√2+2  Answer :  4√2+2