If sin theta = 1/3, then tan theta =
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heya friends✋
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Sin¢=1/3=p/h 【consider as p is perpendicular b is base and h is the height of right angle triangle 】
➡then according to Pythagoras theorm...
b=√h^2-p^2
=>√3^2-1^2
=>√9-1
b=√8=2√2....
now"" tan¢=p/b...
so, tan¢=1/2√2 Ans.
hope it help you...
@Rajukumar☺☺☺
.===============
Sin¢=1/3=p/h 【consider as p is perpendicular b is base and h is the height of right angle triangle 】
➡then according to Pythagoras theorm...
b=√h^2-p^2
=>√3^2-1^2
=>√9-1
b=√8=2√2....
now"" tan¢=p/b...
so, tan¢=1/2√2 Ans.
hope it help you...
@Rajukumar☺☺☺
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3
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