if sin theta = 1/3, then , what is the value of 9/1+cot square Theta ?
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Answer:
The value is 9\cot^2\theta+9=81
Step-by-step explanation:
Given : \sin\theta=\frac{1}{3}
To find : The value of 9\cot^2\theta+9 ?
Solution :
Write the expression as,
9\cot^2\theta+9=9(\cot^2\theta+1)
Using trigonometric property, \cot^2\theta+1=\csc^2\theta
9\cot^2\theta+9=9(\csc^2\theta)
9\cot^2\theta+9=9(\frac{1}{\sin^2\theta})
Substitute the value,
9\cot^2\theta+9=9(\frac{1}{(\frac{1}{3})^2})
9\cot^2\theta+9=9(\frac{1}{\frac{1}{9}})
9\cot^2\theta+9=9(9)
9\cot^2\theta+9=81
Therefore, the value is 9\cot^2\theta+9=81
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