Question

if sin theta =12÷13 find sin^2theta -cos^2 theta÷2 sin theta ×cos theta ×1÷tan^2 theta​

Answer 1

Let x be the adjacent side

By applying Pythagoras

2 = 2 + 2

169 = 144 +

2 = 25

= 5

$cos 0 = \binom{ca}{bc} = \binom{5}{13}$

rest of the answer is in the attachment

Answer 2

Step-by-step explanation:

So, According to the question..

Sin theta=12/13

Sin theta=height/hypotenuse

This means that the height of the triangle is 12

And the hypotenuse of the triangle is 13

Using pythogoras formula,

(Hypotenuse)^2=(height) ^2+(base)^2

(13)^2=(12)^2+(base)^2

169=144+base^2

Base^2=169-144

Base=square root of 25

Base=5

So now, we have to find

=Sin^2theta-cos^2theta÷2sin theta×cos theta ×tan^2theta

=(height/hypotenuse)^2-(base/hypotenuse)^2÷2(height/hypotenuse)×(base/hypotenus)×1÷(height/base)

=(144/169)-(25/169)÷(24/13)×(5/13)×(25/144)

Then you have to solve it and your answer will come..

My work is to give you a hint..