Math, asked by nivyababu1999, 1 year ago

If Sin theta = 12/13 find the value of sin^2 theta-cos^2 theta upon 2 sin theta cos theta - 1/tan^2 theta

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Answered by ajeshrai
9
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Answered by Intelligentman
7

P/b=12/13 h=√313 2 sin theta * cos theta/cos sq theta - sin sq theta 2*p/h * b/h by 1-sin sq. theta-sin sq.theta 2*12/√313*13/√313 by 1- 2 * 12 sq./√313 sq. 312/313 by 1- 2*144/313 312/313-288 312/25

yes the values are correct and the and is 595/3456....i got it

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