if sin theta = 12 upon 3 find the value of sin square tgeta minus cos square theta multiply by i upon tan square theta
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Answer:
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Step-by-step explanation:
sinθ=12/3
∴cos=1/sin
sin²θ-cos²θ.1/tan²θ
=(12/3)²-cos²θ×sin²θ/cos²θ [cos²θ×sin²θ]
=144/9-sin²θ [ cos²θ]
=144/9-144/9
=0
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