Question

if sin theta =2/3, find the value of sec theta and cot theta​

Answer 1

Answer:

sin theta = 2/3 = p/h

h² = p²+b²

(3)² = (2)² + b²

9= 4+b²

9-4 = b²

5 = b²

√5 = b

cos theta = b/h = √5/3

sec theta = h/b = 3/√5

cot theta = b/p = √5/2