If Sin theta = 21/29,prove that sec theta + tan theta =5/2 if theta lies between 0 and pie/2. What will be the value if theta lies (i) between pie and 3pie/2? Hint.part(ii) is impossible. Why y ]
Answers
Answer:
Step-by-step explanation:
sin theta=21/29
⇒opp side=21
⇒hypotenuse=29
⇒adj side=√(29²-21²)
=√(841-441)
=√400
=20
⇒cos theta=20/29
sec theta + tan theta =1/cos theta + sin theta/cos theta
=1/20/29 + 21/29/20/29
=29/20 + 21/20
=50/20
=5/2
since theta lies between 0 to pie/2
all values are positive
part2 is impossible because theta lies first quadrant
the theta values should be positive but in 3rd quadrant sin theta , cos theta
values are negative . so this is impossible
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Step-by-step explanation:
sin theta=21/29,as it lies in first quadrant it will be positive.
by hypotnuse theorem,
we get adjacent side as 20
therefore,
sec theta+tan theta=1/cos theta+sin theta /cos theta
29/20+21/20=50/20=5/2
as it lies between pie and 3pie/2 everythings positive
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