If sin theta =2x & xcos theta= 2, Then find value of
2(x^2+1/x^2
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sin theta = 2x
squaring on both side
sin ^ 2 theeta = 2 { 2x^2}
2x^2 = {sin^2}/2 -------> 1
X^2 = {SIN^2}/4 --------------> 2
NOW GIVEN ::
2 { X^2 + 1 / X^2}
{2 X^2} + {2/X^2] {FROM 1 AND 2}
sin^2/2 + 2/sin^2/4
{sin ^4 + 16}/ 2sin^2
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