Question

if sin theta = √3/2 and cos phi = 1/2 find the value of tan theta - tan phi/1+ tan theta tan phi​

Answer 1

sin theta = (root 3 )/ 2 , theta = 60 degrees

cos phi = 1/2 , phi = 60 degrees

ta. theta - tan phi / 1 + tan theta tan phi = tan ( theta - phi)

= tan(60°-60°) = tan 0 ° = 0

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Answer 2

Answer:

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Step-by-step explanation:

Given :-

$\sin\theta = \frac{ \sqrt{3} }{2} \\ = > \theta = 60°$

$\cos\phi = \frac{1}{2} \\ = > \phi = 60°$

Then ,

$\tan\theta = \tan60° = \sqrt{3} \\ = > \tan\phi = \tan60° = \sqrt{3}$

The value of

$\frac{\tan\theta - \tan\phi}{1 +\tan\theta \tan\phi } \\ = > \frac{ \sqrt{3} - \sqrt{3} }{1 + \sqrt{3}( \sqrt{3} ) } \\ = > \frac{0}{1 + 3} = \frac{0}{4} = 0$