if sin theta =3/4 evaluate root over cosec^2thete-cot^2theta
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Answer:
cosec²-cot²
4/3-√7/3
4-√7/3
4√7/3
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Answer:
Answer is 1.
Step-by-step explanation:
sin theta = 3/4 --> cosec theta = 4/3
cos^2 theta = 1 - sin^2 theta
cos^2 theta = 1 - 9/16
cos^2 theta = (16-9)/16
cos^2 theta= 7/16
cos theta = (7^1/2)/4
cot theta = cos theta / sin theta
= [(7^1/2)/4]/[3/4]
cot theta = (7^1/2)/3
cosec^2 theta - cot^2 theta
= [4/3]^2 - [(7^1/2)/3]^2
= 16/9 - 7/9
= (16-7)/9
= 9/9
= 1
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