Math, asked by sohomharthiqrooshan, 2 months ago

if sin theta =3/4 evaluate root over cosec^2thete-cot^2theta​

Answers

Answered by Devansh1222005
0

Answer:

cosec²-cot²

4/3-√7/3

4-√7/3

4√7/3

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Answered by ranaayushi161
0

Answer:

Answer is 1.

Step-by-step explanation:

sin theta = 3/4 --> cosec theta = 4/3

cos^2 theta = 1 - sin^2 theta

cos^2 theta = 1 - 9/16

cos^2 theta = (16-9)/16

cos^2 theta= 7/16

cos theta = (7^1/2)/4

cot theta = cos theta / sin theta

= [(7^1/2)/4]/[3/4]

cot theta = (7^1/2)/3

cosec^2 theta - cot^2 theta

= [4/3]^2 - [(7^1/2)/3]^2

= 16/9 - 7/9

= (16-7)/9

= 9/9

= 1

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