Question

If sin theta = 3/4 show that root cosec sq theta - cot sq theta / sec sq theta -1 = root 7/ 3

Answer 1

Answer:

hey tushartuli 43........

sinQ=3/4 as p/h .

so according to Pythagoras theorem H square =P square + B square

4×4=3×3+B square

16 =9+B square

16-9=B square

root 7 is Base

so cosec square Q is 16/9 %& cot square Q is 7/ 9( root 7 square is 7 )

so, root 16/9-7/9

root 16-7/9

root 9/9

root 1=1

sec square Q 16/7

as , 1÷16/7 -1

1÷16-7/7

1÷ root 9/7

1÷3/root 7

root7/3 =root7/3

hence proved

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