Question

If sin theta =3/5 and Cos theta =4/5. Find the value of sin squared theta +cos squared theta

Answer 1

${ \sin }^{2} theta + { \cos }^{2} theta \: = 1$

sin=3/5

cos=4/5

$( \frac{3}{5}) {}^{2} + ( \frac{4}{5} ) {}^{2}$

$\frac{9}{25} + \frac{16}{25}$

$\frac{9 + 16}{25}$

we add both with a common denominator as the denominator for both are same...

$\frac{25}{25} = 1$

Hence proved...☺️

Answer 2

The value of sin²Ф+  cos²Ф is 1.

Step-by-step explanation:

We have been given that

$\sin\theta=\frac{3}{5}\\\\\cos\theta=\frac{4}{5}$

Let us find the below values

$\sin^2\theta\\\\=(\frac{3}{5})^2\\\\=\frac{9}{25}$

And

$\cos^2\theta\\\\=(\frac{4}{5})^2\\\\=\frac{16}{25}$

Therefore, we have

$\sin^2\theta+\cos^2\theta\\\\=\frac{9}{25}+\frac{16}{25}$

The denominator of these fractions is same. So, we can directly add the numerators.

Therefore, we have

$\sin^2\theta+\cos^2\theta\\\\=\frac{9+16}{25}\\\\\sin^2\theta+\cos^2\theta=\frac{25}{25}\\\\\sin^2\theta+\cos^2\theta=1$

#Learn More:

Find the value of sin theta + cos theta whole square + cos theta minus sin theta whole square​

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