If sin theta =3/5 and theta is acute angle,find
i)cos theta ii)tan theta
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Answered by
10
FIRST UNDERSTAND THIS THAT TRIGNOMETRY DEALS WITH RIGHT ANGLED TRIANGLE ONLY SO IN THIS TYPE OF QUES. USE THE PYTHAGORAS THEOREM = A2 + B2 = C2
SIN THETA = 3/5 (SIN THETA OF ANY GIVEN ANGLE = PERPENDICULAR/ HYPOTENUSE)
SO IF U HAVE GOT THE PERPENDICULAR AND HYPOTENUSE, FIND THE BASE WHICH WILL DE 4 (AFTER DUE CALCULATION).
THEN COS THETA = 4/5 ( COS OF ANY ANGLE = BASE / PERPENDICULAR)
AND TAN THETA = 3/4 (PERPENDICULAR/ BASE)
Hope ur doubts r cleared. :)
SIN THETA = 3/5 (SIN THETA OF ANY GIVEN ANGLE = PERPENDICULAR/ HYPOTENUSE)
SO IF U HAVE GOT THE PERPENDICULAR AND HYPOTENUSE, FIND THE BASE WHICH WILL DE 4 (AFTER DUE CALCULATION).
THEN COS THETA = 4/5 ( COS OF ANY ANGLE = BASE / PERPENDICULAR)
AND TAN THETA = 3/4 (PERPENDICULAR/ BASE)
Hope ur doubts r cleared. :)
Answered by
4
Cos theta is 4/5
tan theta is 3/4
tan theta is 3/4
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