If sin theta = 3/5 and theta is acute, how do you calculate cos theta and tan theta?
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We will use the Identity :sin2θ+cos2θ=1.
∴cos2θ=1−sin2θ=1−(35)2=1−925=1625
∴cosθ=√1625=±45
But we know that theta is acute , so, it is in the first quadrant, in which, all the Trgo. ratios are +ve
Hence, cosθ=+45.
Finally, tanθ=sinθcosθ..............[Defn.]
=3545=34
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