If sin theta 3/5 find cos theta -1upon tan theta upon 2cot theta
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sin theta equal to 3 by 5 equal to p/H
equal to 3, equal to 5
H square equal to p square + b square
B equal to √H square_p square
= √25_9
=√16
B=4
cos theta =B/H=4/5
tan theta =p/B=3/4
consider=cos theta_1/tan theta/2cot theta
=4/5_1/3/4 /2×4/3
4/5_4/3 / 8/3
12_20/15×3/theta
_theta/5×1/theta
_1/5
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