Question

If sin theta = 3/5 , find the values of cos theta.

Answer 1

Answer:

4/5

Step-by-step explanation:

sin theta = 3/5

making the triangle

sides =  p =3 , 4 , h =5

cos theta = b/h

cos theta = 4/5

Answer 2

Answer:

cos θ = 4/5

Step-by-step explanation:

ΔABC be a right angled at B

Let ∠ACB=θ

Given that, sin θ = 3/5

AB/AC = 3/5

Let AB = 3x

then AC = 5x

In right angled ΔABC,

By Pythagoras theorem,

We get

(5x)^2 =(3x)^2 +BC^2

BC=4x

(i) cos θ = Base/ Hypotenuse

= BC / AC

= 4x /5x

= 4/5