Question

if sin theta =3/5 the value of (1-cos 2 theta) is​

Answer 1

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Given,

$sin \theta \: = \frac{3}{5}$

Now,

$1 - cos \: 2\theta \: \\ = 2 {sin}^{2} \: \theta \: \\ = 2 \times (\frac{3}{5} )^{2} \\ =2 \times \frac{9}{25} \\ = \frac{18}{25}$

Answer 2

Answer:

• sin tita =3÷5. then (1-cos^2tita)=? NOW (1-COS^2tita)=sin^2. then sin^2tita=(3÷5)^2. = 9÷25