Question

if sin theta =3/5 then cos theta will be:​

Answer 1

given★

$\sin(theta) = \frac{3}{5}$

find★

• $\cos(theta)$

solution★

• we know that

$sin(theta) = \frac{3}{5} = \frac{p}{h}$

• p=3

• h=5

• we know that bothayan rules

• $h {}^{2} = b {}^{2} + p {}^{2}$

• $b = \sqrt{h {}^{2} - p {}^{2} }$

• put h and p value

• $b = \sqrt{5 {}^{2} - {3}^{2} }$

• $b= \sqrt{25 - 9}$

• $b = \sqrt{16}$

• $b = 4$

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• we know that

• $\cos(theta) = \frac{b}{h} = \frac{4}{5}$

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other mathod

• we know that

• $\sin {}^{2} (theta) + \cos {}^{2} (theta) = 1 \\ \\ \\ cos {}^{} (theta) = \sqrt{1 - \sin {}^{2} ( theta) }$

• put sin theta value

• $cos(theta) = \sqrt{1 - ( \frac{3}{5} ) {}^{2} }$

• $\cos(theta) = \sqrt{1 - \frac{9}{25} }$

• $\cos(theta) = \sqrt{ \frac{25 - 9}{25} }$

• $\cos(theta) = \sqrt{ \frac{16}{25} }$

• $\cos(theta) = \frac{4}{5}$

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if sin theta =3/5 then cos theta will be=4/5

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I hope it helps you

Answer 2

Answer:

If sin theta = 3//5, find the values of cosine theta. UPLOAD PHOTO AND GET THE ANSWER NOW! Solution : `cos theta =sqrt(1-sin^(2) theta)=sqrt(1-(1)/(9))=pm (2 sqrt(2))/(3)`.