Question

if sin theta=3/5 then find tan theta​

Answer 1

Sin∆ = 3/5

cos∆ = 4/5

Tan∆ = 3/4

Hope it helps you

Answer 2

Hello Mate,

Here is your answer,

Given:

$\sin( \alpha ) = \frac{3}{5} \\ \\ we \: know \\ \\ \sin( \alpha ) = \frac{opposite \: }{hypotenuse} \\ \\ so \\ \\ opposite \: side \: is \: 3 \: units \\ \\ hypotenuse \: is \: 5 \: units \\ \\ we \: have \: to \: find \: the \: adjacent \: side$

$in \: a \: right \: angled \: triangle \\ \\ {a}^{2} + {b }^{2} = {c}^{2} \\ \\ {3}^{2} + {b}^{2} = {5}^{2} \\ \\ {b}^{2} = 16 \\ \\ b = 4 \: units \\ \\ now \: we \: got \: adjacent \: side \: as \: \\ 4 \: units \\ \\ \\ we \: know \: \tan( \alpha ) = \frac{opposite \: side}{adjacent \: side} \\ \\ substituting \: values \: we \: get \\ \\ \tan( \alpha ) = \frac{3}{4}$

Hope it helps:)