If sin theta=4/5 find the value of sin theta tan theta -1 /2tansquare theta
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As We know that the value of sin ∅ = ⅘ as Well.
→ sin ∅ = P/H
→ sin ∅ = ⅘
Now, By using the Pythagoras theorem, we can find the Base of the triangle.
→ H² = B² + P²
→ 5² = B² + 4²
→ 25 = B² + 16
→ 25 - 16 = B²
→ 9 = B²
→ B = 3
Finally, we're going to get the value of sin∅ tan∅ – ½tan²∅
→ ⅘ × 4/3 - ½ × (4/3)²
→ 16/15 - ½ × (16/9)
→ 16/15 – 8/9
→ (48 –40)/45
→ 8/45
Hence,
The value of sin∅ tan∅ – ½tan²∅ is 8/45.
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