If sin theta = - 4/5 Find value of tan theta and cos theta where theta lies ll quadrant
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Step-by-step explanation:
sin©=-4/5
we know
sin²©+cos²©=1
so
(-4/5)²+cos²©=1
cos²© =1-(16/25)
cos²© =9/25
cos© = 3/5
tan ©= 4/3
but in II quadrant
sin©=4/5
cos©=-3/5
tan©=-4/3
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