Question

if sin theta =4/5 then find cos theta​

Answer 1

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Given :-sin theta =4/5

sin theta=perpendicular [P] / hypotenuse [H] =4/5 [see diagram]

perpendicular [P] =4

hypotenuse [H] =5

B^2 =H^- P^2  [by applying Pythagorean Theorem ]

B^2 =5^2 - 4^2

B^2 =[25 - 16] =9

B^2 =√9 =3

cos theta =B/H= 3/5

cos theta = 3/5 ANS

Answer 2

Answer:

is 3÷5

Step-by-step explanation:

in an right angled triangle if we consider a as theta the

sina = opp/hyp

         =4/5

then applying pythagoras theorem we get side = 3

therefor cos theta = adj/hyp

               cosa = 3/5

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