Question

If sin theta = -4/5 then tan theta = .....
(With explaination)​

Answer 1

Answer:

sinA=-4/5 sin^2A+cos^2A=1 cos^2A=1-sin^A=1-(-4/5)^2 cos^2A=1-(16/25) cos^2A=9/25 cosA=3/5 tanA=sinA/cosA tanA=(-4/5)×(5/3) =-4/3 tanA=-4/3