Question

If Sin theta + 40Cos theta = 41, then Cos theta and cosec theta would be?
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Answer 1

Step-by-step explanation:

9sin©+40cos©=41 (1)

9sin©= 41-40cos©

square both side

81sin²©= 1681+1600cos²© -3280cos©

81(1-cos²©)=1681+1600cos²©-3280cos©

81-81cos²©=1681+1600cos²©-3280cos©

1681cos²©-3280cos©+1600=0

(41cos©-40)²=0

41cos©-40=0

41cos©=40

cos©=40/41

now equation 1

9sin©+40cos©=41

9sin©+40(40/41)=41

9sin©=41-1600/41

9sin©=1681-1600/41

9sin©=81/41

sin©=81/41×9

sin©=9/41

cosec©=41/9

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