If sin theta=5/12, then find the value of sin^2 theta- tan^2 theta ?
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Step-by-step explanation:
Given sinthetha=5/12
Sin thetha=opposite to thetha÷hypotenuse
So ,hypotenuse=12 and one side of right angled triangle is 5
5^2+x^2=12^2
25+x^2=144
X^2=119
X=root of 119
Means x=adjacent to thetha
Tan thetha=opposite to thetha÷side adjacent to thetha
Tan thetha=5/root of 119
Sin^2thetha=(5/12)^2
Sin^2thetha=25/114
Tan^2thetha=(5/root of 119)^2
Tan^2thetha=25/119
Sin^2thetha+tan^2thetha=25/144+25/119
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