If sin theta = 5/12 then find the value of tantheta - cot theta?
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Answer:
sin theta=5/12=p/h
b=√(h) ^2-(p) ^2=√(12) ^2-(5) ^2=144-25=√119
tan theta=p/b=5/√119
cot theta=b/p=√119/5
tan theta-cot theta
=5/√119-√119/5
=25-119/5√119
=-94/5√119
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Step-by-step explanation:
we have use sin theta which is p/h and from there we find base by pythagoras theorem and that make your question simple
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