if sin theta =-5/13 and theta us in the third quadrant , then prove that 5cotsquare theta + 12tan theta + 13cosec theta=0
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Given:
sinθ = −5/13 and θ is in the third quadrant.
To Prove:
5cot^2θ+12tanθ+13cosecθ=0.
Proof:
In 3rd quadrant, only tanθ and cotθ are positive.
sin^2θ + cos^2θ = 1
=> cos^2θ = 1 - (-5/13)^2
=> cos^2θ = (12/13)^2
=> cosθ = -12/13 (As cosθ is negative in 3rd quadrant)
- tanθ = sinθ/cosθ = 5/12
- cotθ = 1/tanθ = 12/5
- cosecθ = 1/sinθ = -13/5
5cot^2θ+12tanθ+13cosecθ
= 5(12/5)^2 + 12(5/12) + 13(-13/5)
= 144/5 + 5 - 169/5
= -25/5 + 5
= -5 + 5
= 0
Hence, it is proved.
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