Question

if sin theta = 5/13 find the value of sec theta and cot theta​

Answer 1

Answer:

sin theta=5/13

in a triangle ABC,

let AB=5 BC=13 and AC= √ BC^2 -AB^2 (Pythagoras theorem)

AC=12

cos theta=12/13

tan theta=5/12

cosec theta=13/5

sec theta=13/12

cot theta=12/5

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

sin o=5/13 (x^2+5^2=13^2 => x=12)

cos o =12/13

tan o = 5/12

seco= 1/coso= 13/12

cot o= 1/tano =12/5