Question

if sin theta= 5/13
find the value of tan theta+ 1/ cos theta

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Answer 1

Given that :

SinA = 5/13 = P/H

By Pythagoras theoram :

H² = P²+B²

=> 13² = 5²+B²

=> B² = 169-25 = 144

=> B = 12

then, tanA = P/B = 5/12 and cosA = B/H = 12/13

Now, tanA + 1/cosA

$= > \frac{5}{12} + \frac{1}{ \frac{12}{13} } \\ \\ = > \frac{5}{12} + \frac{13}{12} \\ \\ = > \frac{18}{12} = \frac{3}{2}$

I hope it will be helpful for you ✌️✌️

Mark it as brainliest and.....

Fóllòw MË ☺️☺️

Answer 2

Answer:

WE HAVE sinθ = perpendicular  /  hypotenuse

                  >> sinθ = 5 /13

so, by pythagoras theorem,

  hypotenuse²=perpendicular²+base²

   >>   13²=5²+b²

 >>  169-25=b²

 >>   144 = b²

  >>  b=12

   

Step-by-step explanation:

hence,

  >>  tanθ =5 / 12

   >> cosθ = 12 / 13

putting values,

      >>     (  5 / 12) + 1 / (12 / 13)

        >>    (5 / 12) + (13/ 12)

       >>   18 / 12

       >>  3 /2

   

       

i hope it helps.