Question

if sin theta =a/b, find sec theta +tan theta in terms of a and b?​

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

$\sin(theta) = \frac{a}{b} \\ so \: \: \sec(theta) = \frac{b}{ \sqrt{( {b}^{2} - {a}^{2} )} } \\ and \\ \tan(theta) = \frac{a}{ \sqrt{( {b}^{2} - {a}^{2} )} } \\ now \: \sec(theta) + \tan(theta )\\ = \frac{b}{ \sqrt{( {b}^{2} - {a}^{2}) } } + \frac{a}{ \sqrt{( {b}^{2} - {a}^{2} )} } \\ = \frac{b + a}{ \sqrt{( {b}^{2} - {a}^{2} ) } }$

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