Question

If sin theta =a/b find sec theta +tan theta in terms of a and b​

Answer 1

Answer:

Step-by-step explanation:

The answer is given below :

sinθ = a/b

So, secθ = b/√(b² - a²)

and

tanθ = a/√(b² - a²)

Now,

secθ + tanθ

= b/√(b² - a²) + a/√(b² - a²)

= (b + a)/√(b² - a²)

Answer 2

Step-by-step explanation:

sin theta=a/b

perpendicular /hypotenuse =a/b

base=(b²-a²)½

sec theta= b/(b²-a²)½

tan theta=a/(b²-a²)½

sec theta +tan theta= (a+b)/(b²-a²)

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