If Sin theta=a/b,then cos theta =?
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Answer:
√(b²-a²)/b
Step-by-step explanation:
sinθ=a/b
∴, cosθ=√(1-sin²θ) [∵, sin²θ+cos²θ=1]
or, cosθ=√(1-a²/b²)
or, cosθ=√{(b²-a²)/b²}
or, cosθ=√(b²-a²)/b
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9
Answer:
Here's your answer.
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