if sin theta = a/b then cos theta=
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sin θ =a/b
We know, sin² θ + cos² θ = 1
sin² A = 1 - cos² A
sin A = √(1-cos² A
So, cos θ = √(1 - a²/b²) = √((b² - a²)/b²) = √(b² - a²)/b
Hence, cos θ = √(b² – a²)/b
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