Question

if sin theta =a/b then find the value of sec theta +tan theta​

Answer 1

Step-by-step explanation:

sec theta + tan theta=

cos theta /sin theta + sin theta / cos theta

cos^2 theta + sin ^2 theta/sin theta ×cos theta

1/cos theta ×a/b

1/ a cos theta /b

b/ a cos theta

Answer 2

Answer:

b+a

√b^2-a^2

Step-by-step explanation:

sin°=a\b

sec°+tan°

1\cos°+sin°\cos°

1+sin°

cos°

1+a/b

cos°

sin^2°+cos^2°=1

b+a

b.

cos°

b+a

b.

√b^2-a^2

b

b+a

√b^2-a^2

cos^2°=1-sin^2°

cos^2°=1-a^2

b^2°

cos^2°=b^2°-a^2°

b^2°

cos°=√b^2°-a^2°/√b^2°

cos°= √ b^2-a^2/b