Question

if sin theta=a/b ,then the value of sec theta

Answer 1

sin 0 = a/b

sin^2 0= a^2/b^2

-sin^2 0= -a^2/b^2 multiplying - from both sides

add one on both sides

1-sin^0= 1 -a^2/b^2

cos^2 0= 1 -a^2/b^2

cos 0 = root( 1 -a^2/b^2)

sec 0 =1/root( 1 -a^2/b^2)

note that 0 means theta

hope this is right