If sin theta = a/b, then what is the value of cos theta?
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Step-by-step explanation:
Sin theta = P/H = a/b
Base = √h²-p²
= √b²-a²
Cos theta = B/H
= √b²-a²/b
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sin theta = a/b
sin theta = perpendicular/hypotenuse
p=a
h=b
cos theta = base/hypotenuse
base = square root of b^2-a^2
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