Math, asked by harshojha5050, 9 months ago

If sin theta = a/b, then what is the value of cos theta?

Answers

Answered by zaidkhan01
0

Step-by-step explanation:

Sin theta = P/H = a/b

Base = √h²-p²

= √b²-a²

Cos theta = B/H

= √b²-a²/b

Answered by LalitmGoyal
0

sin theta = a/b

sin theta = perpendicular/hypotenuse

p=a

h=b

cos theta = base/hypotenuse

base = square root of b^2-a^2

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