Question

If sin theta = a square - b square / a square + b square, find the value of all t-ratios of theta.

Answer 1

Step-by-step explanation:

Step-by-step explanation:

We know that,

Sin ¢ = p/h Cosec ¢ = h/p

Cos ¢ = b/h Sec ¢ = h/b

tan ¢ = p/b Cot ¢ = b/p

Here P = perpendicular, b= base and h = hypotenuse.

....................................................................

Given, Sin ¢ = (a² - b²) / (a² + b²)

here, perpendicular (p) = (a² - b²) and hypotenuse (h) = (a² + b²)

by, Pythagoras theorem.

base (b) = √(a² - b²)² + (a² - b²)²

base (b) = 2ab

Now...

Cos ¢ = (2ab) / (a² + b²)

tan ¢ = (a² - b²) / 2ab

Cosec ¢ = (a² + b²)/ (a² - b²)

Sec ¢ = (a² + b²)/ 2ab

cot ¢ = 2ab / (a² - b²)

Answer 2

Answer:

Step-by-step explanation:

We know that,

Sin ¢ = p/h Cosec ¢ = h/p

Cos ¢ = b/h Sec ¢ = h/b

tan ¢ = p/b Cot ¢ = b/p

Here P = perpendicular, b= base and h = hypotenuse.

Given, Sin ¢ = (a² - b²) / (a² + b²)

here, perpendicular (p) = (a² - b²) and hypotenuse (h) = (a² + b²)

by, Pythagoras theorem.

base (b) = √(a² - b²)² + (a² - b²)²

base (b) = 2ab

Now...

Cos ¢ = (2ab) / (a² + b²)

tan ¢ = (a² - b²) / 2ab

Cosec ¢ = (a² + b²)/ (a² - b²)

Sec ¢ = (a² + b²)/ 2ab

cot ¢ = 2ab / (a² - b²)

Step-by-step explanation:

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