Question

If sin theta = a2-b2/a2+b2 find the values of all T-ratio​

Answer 1

Answer:

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Step-by-step explanation:

We have, sin A = Perpendicular  / Hypotenuse  = a2-b2 / a2+b2  

So, we draw a right triangle right angled at B such that

Perpendicular = a2-b2 and , Hypotenuse = a2+b2  and ∠BAC=θ

By Pythagoras theorem, we have

AC^2 = AB^2 - BC^2

AB^2 = (a^2 + b^2)^2 - (a^2 - b^2)^2

AB^2 = (a^4 + b^4 + 2a^2b^2) - (a^4 + b^4 - 2a^2b^2)

AB^2 = 4a^2b^2 =(2ab) ^2

AB = 2ab

When we consider the trigonometric ratios of ∠BAC=θ  , we have

Base = AB = 2ab, Perpendicular = BC = a^2 - b^2 , and Hypotenuse = AC = a^2 + b^2

REFER TO  1ST IMAGE

Answer 2

Answer:

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Step-by-step explanation:

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