Question

If sin theta =a2-b2/a2+b2 .To find cos theta .tan theta .please answer the question fast​ with explation

Answer 1

Answer:

cos theta ,= 2ab/ a2+b2

tan theta = a2-b2 / 2ab

Step-by-step explanation:

sin theta^2 + cos theta^2 = 1

-> I - costheta^2 = (a2-b2/ a2 +b2) ^2

-> (a4 + b4 +2a2b2 -a4 - b4 + 2a2b2)/ (a2+ b2)^2 = costheta square

-> (2ab/a2+ b2) sq= (cos theta)sq

-> cos theta = 2ab/ a2+b2

tan theta = sin theta / cos theta

> tan theta = (a2-b2)(a2+b2)/ (a2+b2)2ab = a2- b2 / 2ab