if sin theta +cos heta=root 2 find tan theta+cot theta
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☸ Required Answer is ⬇ ⬇⬇ ⬇
Given,
sin¢ + cos¢ =√2
Squaring both sides,
(sin¢+cos¢)² = (√2)²
sin²¢ + cos²¢ +2sin¢.cos¢ = 2
1 + 2sin¢.cos¢ = 2
2sin¢.cos¢ = 1
sin¢.cos¢ = 1/2
=> tan¢ + cot¢ = ?
=> sin¢/cos¢ + cos¢/sin¢
=> sin²¢ + cos²¢ / cos¢.sin¢
=> 1/ 1/2
=> 2
tan¢ + cot¢ = 2
Vielen Dank ♥
☸ Required Answer is ⬇ ⬇⬇ ⬇
Given,
sin¢ + cos¢ =√2
Squaring both sides,
(sin¢+cos¢)² = (√2)²
sin²¢ + cos²¢ +2sin¢.cos¢ = 2
1 + 2sin¢.cos¢ = 2
2sin¢.cos¢ = 1
sin¢.cos¢ = 1/2
=> tan¢ + cot¢ = ?
=> sin¢/cos¢ + cos¢/sin¢
=> sin²¢ + cos²¢ / cos¢.sin¢
=> 1/ 1/2
=> 2
tan¢ + cot¢ = 2
Vielen Dank ♥
thank you @ROYALTANWAR
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