If sin theta-cos theta=0,then find the value of sin ^4 theta+cos^4 theta
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Given that, sin θ – cos θ = 0
sin θ = cos θ
sin θ / cos θ = tan θ
=> tan 45° = 1
=> θ = 45°
Now,
sin⁴ θ + cos⁴ θ
= ( sin² θ )² + ( cos² θ )²
= ( sin² 45° )² + ( cos² 45° )²
= [ ( 1 / √2 )² ]² + [ ( 1 / √2 )² ]²
= ( 1 / 2 )² + ( 1 / 2 )²
= ( 1 / 4 ) + ( 1 / 4 )
= ( 1 + 1 ) / 4
= 2 / 4
= 1 / 2
Given that, sin θ – cos θ = 0
sin θ = cos θ
sin θ / cos θ = tan θ
=> tan 45° = 1
=> θ = 45°
Now,
sin⁴ θ + cos⁴ θ
= ( sin² θ )² + ( cos² θ )²
= ( sin² 45° )² + ( cos² 45° )²
= [ ( 1 / √2 )² ]² + [ ( 1 / √2 )² ]²
= ( 1 / 2 )² + ( 1 / 2 )²
= ( 1 / 4 ) + ( 1 / 4 )
= ( 1 + 1 ) / 4
= 2 / 4
= 1 / 2
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