If sin theta-cos theta = 0,then the value of (sin4 theta + cos4 theta) is
Answers
Answered by
1379
Hey there !!!!!!
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sinθ-cosθ = 0
sinθ= cosθ
sinθ/cosθ = 1
tanθ = 1
Bu tan45 = 1
So,
tanθ=tan45
θ = 45°
sin45 = 1/√2 cos45 = 1/√2
sin⁴θ+cos⁴θ = (1/√2)⁴+(1/√2)⁴
= 1/4+1/4 = 2/4 = 1/2 = 0.5
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Hope this helped you..................
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
sinθ-cosθ = 0
sinθ= cosθ
sinθ/cosθ = 1
tanθ = 1
Bu tan45 = 1
So,
tanθ=tan45
θ = 45°
sin45 = 1/√2 cos45 = 1/√2
sin⁴θ+cos⁴θ = (1/√2)⁴+(1/√2)⁴
= 1/4+1/4 = 2/4 = 1/2 = 0.5
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Hope this helped you..................
Answered by
686
Hi
___________________________
Sin theta - Cos theta = 0
Sin45° - Cos45° = 0
then
Sin⁴theta + cos⁴theta
= sin⁴45° + cos⁴45°
= (1/√2)⁴ + (1/√2) ⁴
= 1/4+ 1/4
= 2/4
= 1/2
___________________________
Sin theta - Cos theta = 0
Sin45° - Cos45° = 0
then
Sin⁴theta + cos⁴theta
= sin⁴45° + cos⁴45°
= (1/√2)⁴ + (1/√2) ⁴
= 1/4+ 1/4
= 2/4
= 1/2
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