if sin theta-cos theta=1, find the value of cos theta + sin theta
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Step-by-step explanation:
Sin A - cos A = 1
squaring
Sin²A + Cos²A - 2sinAcosA = 1²
1 - 2sinAcosA = 1
-2sinAcosA =1 - 1
cosAsinA = 0
sin A + cosA
sq.uaring
Sin²A + Cos²A + 2sinAcosA
1 + 2(0)
1
(sin A + cosA )² = 1
sin A + cosA = √1 = +1,-1
{[( Sin²A + Cos²A = 1 )]}
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