if sin theta +Cos theta = √3, then prove that tan theta + cot theta = 1
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sin θ + cos θ = √3
square both sides. Use sin^2 θ + cos^2 θ = 1
1 + 2 sin θ cos θ = 3
sin θ cos θ = 1
---------------------
tan θ + cot θ =
(sin θ / cos θ) + (cos θ / sin θ) =
(sin^2 θ + cos^2 θ) / (sin θ cos θ) =
1/1 =
1
...
thank u
square both sides. Use sin^2 θ + cos^2 θ = 1
1 + 2 sin θ cos θ = 3
sin θ cos θ = 1
---------------------
tan θ + cot θ =
(sin θ / cos θ) + (cos θ / sin θ) =
(sin^2 θ + cos^2 θ) / (sin θ cos θ) =
1/1 =
1
...
thank u
Anonymous:
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